Vainly tried to find a solution for the following problem.
Rename file
fm: file name blah blah 100222.txt
to: file name blah blah 10022022.txt
Keeping it simple I would go for
find: (.+)(\d\d).(\w+)
however, in the replace \1 and adding the 20 to the year is posing a problem
believe using \ parameters is limited to 9 or 10 ?
how to add the 20 then?
Thanks.
Thank you very much!
Solved.
Hope one day another regex style supporting $ will be allowed....
Anyway, thanks again.
What difference would $ vs \ make here?
Ai!
I just noticed, I was in the wrong regex rename mode...
tsk tsk tsk...
Pretty embarrassing.
From what I remember, a lllong time ago, there was something with the maximum groups, or something and one could only use upto \9 ...(?)
Hence when nothing happed when trying \20 I wrongly assumed I hit on this 'limitation', but did not realize I was using the wrong mode.
Very sorry for the confusion.
You’re only using 3 groups so the limit of 9 replacement groups wouldn’t be an issue.
\20 would insert group 2 and then a zero.
